Time
15 hours 34 minutes
Difficulty
Intermediate
CEU/CPE
16

Video Description

EIGRP Manual Summarization In this lesson we cover Manual Summarization of the EIGRP protocol process. You'll learn how to mathematically map out the process of 3 networks in this topology examination.

Video Transcription

00:04
so the next topic of discussion is going to be E I G R P manual summarize ation.
00:10
Now let's pretend there are three networks that exist in our topology, and I'm gonna create them in a little bit.
00:15
And they are networks 30.10 not 8.0 with an i p address 0.8. Then it were 30 dot Tenn 30.0.9 dot nine, with the network out of 30 that with the network address of 30 that 10.90
00:31
and another network with a network Anders of 30 dot Tenn dot Tenn 30.0.0.0. With the I P address being 0.10 seances, these all three are slashed 24 networks or 2552552550
00:46
Now let's say
00:48
these networks exists in my anthropology
00:51
and
00:53
someone,
00:55
some other network administrator tells me, or some other network engineer tells me, Please stop cluttering up my routing table with all three of these networks and please summarize them into one address and send me that one address.
01:11
So how do I go ahead and summarize three networks, three different networks into one address?
01:18
Well, let's look at which octet is different
01:23
on these three networks, so this network isn't or 30 dot Tenn dot a 30.0.0.0. There's no organs 30 10 not 9.0, and the last one is 30 to $10.10 dollars. Zero.
01:34
So if you see the first art, it's the same.
01:38
The second test the same. It's the third octet. That's changing.
01:42
So I have drawn out three octet. It's
01:46
I've drawn out the third octet for each one of these networks.
01:49
So this is going to be the
01:53
Value eight
01:55
in the third Octet Network.
01:57
This is going to be the value nine in the cellar Doctor Network.
02:00
And this is going to be the value 10
02:04
for 0.8 dot 9.10.
02:07
Now, how do I get eight? Turn the eight
02:10
bit on and the rest of from our zeros.
02:19
How do I get nine? I get the H and the one bit on on the rest of him
02:24
are zeros.
02:29
I turned the eight and two bit on to get 10
02:32
and the rest of foam are zeros.
02:39
So as you see my ones lying up
02:44
at the age of its value,
02:46
so my summarized network address would be 30
02:51
0.10
02:53
0.8
02:55
0.0
02:59
and my mask is going to change to remember, this is the third octet for all three networks. My mask is going to change, too.
03:07
True. 55
03:09
not 255 because the 1st 2 Arquette's of Completely Masked
03:15
is 1/3 octet that we're working in.
03:19
So at the end, bit value. If I add all these up 1 28 plus 64 plus 32 plus 16 plus eight, I get
03:28
true. 48.0
03:34
or a slash eight
03:37
plus 80 16 17 18 1920 21 or a slash 21 network.
03:45
Now let's go ahead and see how this works on our lap.

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Junaid Memon
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