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This topic contains 8 replies, has 8 voices, and was last updated by  jrosse 1 year, 4 months ago.

Viewing 9 posts - 1 through 9 (of 9 total)
  • Author
    Posts
  • #62613

    throne-85
    Participant

    From your explanation, if i subnet a class c ip address with /30 how many IP address am i supposed to have owing to the fact i have 64 subnets.

    #62656

    vant00ra
    Participant

    Maybe you can try with your mask first:
    ? . ? . ? . ? = /30
    255.231.0.0

    #62701

    Brian Idol
    Participant

    Assuming you have an entire Class C network to work with (i.e. 192.168.0.0/16), if you subnet it down to /30, this will give you 16384 individual networks to work with (192.168.0.0-192.168.255.252). The down side to this is that each individual network will only have 4 IP addresses, of which only 2 will be usable. Not really functional within corporate networks, however this is great from a security perspective for a point-to-point connection such as 2 VPN concentrators at 2 different sites.

    Not sure if that answers your question or not, but let me know and I’ll help as much as I can.

    #62734

    Dragon
    Participant

    CIDR Range 192.168.1.0/30
    Netmask 255.255.255.252
    Wildcard Bits 0.0.0.3
    First IP 192.168.1.0
    Last IP 192.168.1.3
    Total Host 4

    CIDR Range 192.168.1.0/2
    Netmask 192.0.0.0
    Wildcard Bits 63.255.255.255
    First IP 192.0.0.0
    Last IP 255.255.255.255
    Total Host 1073741824

    There are calculators for this if you want to experiment with it.
    http://www.ipaddressguide.com/cidr

    #62831

    Paul Rouk
    Participant

    You should take a look at the table linked below which shows how many IP addresses and subnets you have for each mask. For a mask of /30, you only have 2 usable IP addresses per subnet.

    https://www.aelius.com/njh/subnet_sheet.html

    #81420

    throne-85
    Participant

    thanks guy i have been ill just saw your responses it really helped… u guys rock.

    #99606

    gabenet123
    Participant

    quick question or clarification on the example he used. the last but one broadcast address shouldn’t it be .223, if my understanding is right the broadcast address is supposed to be the last octet of the next group minus 1 in which case it would be 223 not 224. if my understanding is wrong can someone kindly clarify things for me.

    #112349

    francisco3dwork
    Participant

    Hello ! Somebody know how to take the test for the certfication on subnetting skill certification appear on the top of module 2? It doen´t work properly.

    #113109

    jrosse
    Participant

    I am taking a class at school, and the professor assigned a test question with a CIDR of /6

    How many hosts will that support? All the cheat sheets I found supported down to 8

    –Jim R

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